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WGU Scripting and Programming Foundations Exam Sample Questions (Q81-Q86):

NEW QUESTION # 81
Which kind of language is HTML?

  • A. Statically typed
  • B. Object-oriented
  • C. Markup
  • D. Dynamically typed

Answer: C

Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
HTML (HyperText Markup Language) is a standard for structuring content on the web. According to foundational programming principles, HTML is a markup language, not a programming language, and does not involve typing (dynamic or static) or OOP.
* Option A: "Dynamically typed." This is incorrect. HTML is not a programming language and does not involve variables or typing. Dynamic typing applies to languages like Python or JavaScript.
* Option B: "Markup." This is correct. HTML is a markup language used to define the structure of web content using tags (e.g., <p>, <div>).
* Option C: "Statically typed." This is incorrect. HTML does not involve typing, as it is not a programming language. Static typing applies to languages like C or Java.
* Option D: "Object-oriented." This is incorrect. HTML lacks OOP features like classes, inheritance, or polymorphism, as it is designed for content structuring, not programming.
Certiport Scripting and Programming Foundations Study Guide (Section on Markup Languages).
W3Schools: "HTML Introduction" (https://www.w3schools.com/html/html_intro.asp).
Mozilla Developer Network: "HTML Basics" (https://developer.mozilla.org/en-US/docs/Learn
/Getting_started_with_the_web/HTML_basics).


NEW QUESTION # 82
A particular sorting takes integer list 10,8 and incorrectly sorts the list to 6, 10, 8.
What is true about the algorithm's correctness for sorting an arbitrary list of three integers?

  • A. The algorithm is incorrect
  • B. The algorithm's correctness is unknown
  • C. The algorithm is correct
  • D. The algorithm only works for 10,6, 8

Answer: A

Explanation:
The correctness of a sorting algorithm is determined by its ability to sort a list of elements into a specified order, typically non-decreasing or non-increasing order. For an algorithm to be considered correct, it must consistently produce the correct output for all possible inputs. In the case of the given algorithm, it takes the input list [10, 8] and produces the output [6, 10, 8], which is not sorted in non-decreasing order. This indicates that the algorithm does not correctly sort the list, as the output is neither sorted nor does it maintain the integrity of the original list (the number 6 was not in the original list).
Furthermore, the fact that the output contains an integer (6) that was not present in the input list suggests that the algorithm is not preserving the elements of the input list, which is a fundamental requirement for a sorting algorithm. This violation confirms that the algorithm is incorrect for sorting an arbitrary list of three integers, as it cannot be relied upon to sort correctly or maintain the original list elements.


NEW QUESTION # 83
Which kind of languages are C, C++ and Java?

  • A. Interpreted
  • B. Markup
  • C. Machine code
  • D. Compiled

Answer: D

Explanation:
C, C++, and Java are all considered compiled languages. This means that the code written in these languages is not executed directly by the hardware but must first be translated into machine code by a compiler.
* C is a general-purpose programming language that is compiled to generate machine code which can be executed directly by the computer's CPU1.
* C++ is an extension of C that includes object-oriented features. It is also a compiled language, where the source code is converted into machine code that can be executed by the CPU2.
* Java is a bit unique because it is compiled into bytecode, which is then run on a virtual machine (JVM) rather than directly by the CPU. However, it is still considered a compiled language because the source code is compiled before it is executed2.
References:
* Understanding of the compilation process for C, C++, and Java.
* Official documentation and language specifications for C, C++, and Java.
* Articles and resources on programming language paradigms and compiler design.


NEW QUESTION # 84
What is the proper way to declare a student's grade point average throughout the term if this item is needed in several places in a program?

  • A. Constant float gpa
  • B. Variable int gpa
  • C. Constant int gpa
  • D. Variable float gpa

Answer: D

Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
A grade point average (GPA) is a numerical value that typically includes decimal places (e.g., 3.75).
According to foundational programming principles, it should be declared as a variable if it may change (e.g., as grades are updated) and as a floating-point type to accommodate decimals.
* Option A: "Variable float gpa." This is correct. GPA requires a floating-point type (float) to handle decimal values, and since it may change over the term, it should be a variable, not a constant. For example, in C: float gpa = 3.5;.
* Option B: "Constant float gpa." This is incorrect. A constant (const in C) cannot be modified after initialization, but GPA may change as new grades are added.
* Option C: "Variable int gpa." This is incorrect. An integer (int) cannot store decimal values, which are common in GPAs (e.g., 3.2).
* Option D: "Constant int gpa." This is incorrect. GPA requires a float for decimals and a variable for mutability, making both const and int unsuitable.
Certiport Scripting and Programming Foundations Study Guide (Section on Variables and Data Types).
C Programming Language Standard (ISO/IEC 9899:2011, Section on Floating Types).
W3Schools: "C Variables" (https://www.w3schools.com/c/c_variables.php).


NEW QUESTION # 85
Which line is a loop variable update statement in the sample code?
integer h = 0
do
Put "What is the password?" to output
String userInput = Get next input
if userInput != pwd
Put "Incorrect." to output
h = h + 1
while (userInput != pwd) and (h <= 10)
if userInput = pwd
Put "Access granted." to output
else
Put "Access denied." to output

  • A. integer h = 0
  • B. if userInput = pwd
  • C. h = h + 1
  • D. (userInput != pwd) and (h <= 10)

Answer: C

Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
The loop variable update statement modifies the loop control variable to progress the loop. In this do-while loop, h tracks the number of attempts, and its update is critical to the loop's termination. According to foundational programming principles, the update statement is typically within the loop body.
* Code Analysis:
* integer h = 0: Initializes h (not an update).
* Put "What is the password?" to output: Outputs prompt (not an update).
* String userInput = Get next input: Gets input (not an update).
* if userInput != pwd: Conditional check (not an update).
* Put "Incorrect." to output: Outputs message (not an update).
* h = h + 1: Updates h, incrementing the attempt counter.
* while (userInput != pwd) and (h <= 10): Loop condition (not an update).
* Option A: "if userInput = pwd." Incorrect. This is a conditional statement, not an update. (Note: The code uses = for comparison, which may be a typo; == is standard.)
* Option B: "h = h + 1." Correct. This updates the loop variable h, incrementing it to track attempts.
* Option C: "(userInput != pwd) and (h <= 10)." Incorrect. This is the loop condition, not an update.
* Option D: "integer h = 0." Incorrect. This is the initialization, not an update.
Certiport Scripting and Programming Foundations Study Guide (Section on Loops and Variables).
C Programming Language Standard (ISO/IEC 9899:2011, Section on Do-While Loops).
W3Schools: "C Do While Loop" (https://www.w3schools.com/c/c_do_while_loop.php).


NEW QUESTION # 86
......

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